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Cgu, ank sy dlm thn 5 dan lmh dlm sub sains.. Sy amat ssh hati krn thn dpn dia pula akan mnduduki upsr. sy mncari2 tips utk sy praktikkn pd ank sy dan di ruangan ini sy temui segalanya.. Ats usaha cgu ini sy mndpt bnyk pengetahuan.. Terima kasih ats usaha cgu semoga diberkati segala ilmu yg dikongsikan brsama... (ummiS 8sept11 12.14am) Klik
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PMR - Mathematics question no.4
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PMR - Mathematics question no.4
by Cikgu Edy on Sun May 18, 2008 4:42 pm
Ok guys... try this again
_________________mbf...
Be Joyful always...
Cikgu Edy- Moderator
- Number of posts: 967
Humor: hiiii hiii . nobody's perfect laa...
Registration date: 08/05/2008 
Re: PMR - Mathematics question no.4
by Cikgu Edy on Tue May 20, 2008 4:07 pm
Tips menjawab soalan di atas...
= 2(Y x Y x Y) [1 - (Y) ]
= gantikan Y dengan -1
= .... cuba teruskan... nanti cikgu bantu... jangan takut untuk menjawab sebab lebih baik salah menjawab pada ketika ini daripada salah menjawab semasa peperiksaan besar nanti...
selesaikan yang berwarna biru terlebih dahulu.
= 2(Y x Y x Y) [1 - (Y) ]
= gantikan Y dengan -1
= .... cuba teruskan... nanti cikgu bantu... jangan takut untuk menjawab sebab lebih baik salah menjawab pada ketika ini daripada salah menjawab semasa peperiksaan besar nanti...
selesaikan yang berwarna biru terlebih dahulu.
_________________mbf...
Be Joyful always...
Cikgu Edy- Moderator
- Number of posts: 967
Humor: hiiii hiii . nobody's perfect laa...
Registration date: 08/05/2008 -
Re: PMR - Mathematics question no.4
by syahrom on Sun Aug 02, 2009 7:59 am
the answer is C=0
jln kira,
=-2(-1x-1x-1)[1-(-1)]
=-2(-1)[1-(-1)]
=2[1-(-1)]
=[2+(-2)]
=[2-2]
=0
jln kira,
=-2(-1x-1x-1)[1-(-1)]
=-2(-1)[1-(-1)]
=2[1-(-1)]
=[2+(-2)]
=[2-2]
=0
syahrom- MBF New Member
- Number of posts: 2
Registration date: 02/08/2009 -
Re: PMR - Mathematics question no.4
by Cikgu Edy on Mon Aug 03, 2009 11:37 am
syahrom wrote:the answer is C=0
jln kira,
=-2(-1x-1x-1)[1-(-1)]
=-2(-1)[1-(-1)] ....ok
=2[1-(-1)].... semak semula, bukan begini caranya....
=[2+(-2)]
=[2-2]
=0
lihat komen warna biru
terimakasih kerana menjawab, silalah buat lagi supaya cikgu dapat membantu...
_________________mbf...
Be Joyful always...
Cikgu Edy- Moderator
- Number of posts: 967
Humor: hiiii hiii . nobody's perfect laa...
Registration date: 08/05/2008 -
Re: PMR - Mathematics question no.4
by Cikgu Edy on Tue Oct 06, 2009 7:19 am
adah wrote:agak susa soklan nii
cuba saja... nanti cikgu akan komen....
_________________mbf...
Be Joyful always...
Cikgu Edy- Moderator
- Number of posts: 967
Humor: hiiii hiii . nobody's perfect laa...
Registration date: 08/05/2008 -
Re: PMR - Mathematics question no.4
by nurizni on Tue Jul 20, 2010 2:09 am
jawapan saya
B. -4
if y=-1 , then 2y³(1-y)
= 2(-1)³(1-(-1)
= 2 (-1)(1+1)
= 2 x -1 x 2
= -2 x 2
= -4
it right?
B. -4
if y=-1 , then 2y³(1-y)
= 2(-1)³(1-(-1)
= 2 (-1)(1+1)
= 2 x -1 x 2
= -2 x 2
= -4
it right?
nurizni- MBF New Member
- Number of posts: 11
Age: 16
Registration date: 27/06/2010 -
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