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tolong saya selesaikan soalan ni..
Page 1 of 1 • Share •
tolong saya selesaikan soalan ni..
sape boleh tolong saya selesaikan soalan pecahan ni..xfaham la cemana nak selesaikan..
5⅙-3⅔
tq
5⅙-3⅔
tq
harith_azka- MBF New Member

- Number of posts: 4
Registration date: 08/12/2010
Re: tolong saya selesaikan soalan ni..
jawapannya
=round offkan soalan.31 per 6 tolak dengan 11 per 3 sebelum tu 31/6 kali dengan 3 & 11/3 kali dengan 6.selepas tu tolak ke2 2 jawapan.kecilkan jawapan.
harap iana dapat membantu.
=round offkan soalan.31 per 6 tolak dengan 11 per 3 sebelum tu 31/6 kali dengan 3 & 11/3 kali dengan 6.selepas tu tolak ke2 2 jawapan.kecilkan jawapan.
harap iana dapat membantu.
miss_illiana- MBF Junior Member

- Number of posts: 30
Age: 15
Location: taiping perak
Registration date: 18/11/2010
Re: tolong saya selesaikan soalan ni..
masih belum dapat membantu la..ikut jawapan dari buku ialah 1 1/2..cemana ni.buntu fikiran...
harith_azka- MBF New Member

- Number of posts: 4
Registration date: 08/12/2010
Re: tolong saya selesaikan soalan ni..
harith_azka wrote:sape boleh tolong saya selesaikan soalan pecahan ni..xfaham la cemana nak selesaikan..
5⅙-3⅔![]()
tq
tukarkan dulu kpd pecahan tdk wajar...
= (6 x 5 + 1 per 6) - (3 x 3 + 2 per 3)
= 31/6 - 11/3
tdk boleh selesaikan kerana pembawah tdk sama...
maka, samakan pembawah...
= 31/6 - (11/3)darabkan dgn 2
= 31/6 - (11x2)/(3x2)
= 31/6 - 22/6
= (31-22)/6
= 9/6
= 1 3/6
ringkaskan lagi...
= 1 1/2...#
_________________mbf...


Cikgu X- Special Rank
- Number of posts: 3180
Registration date: 12/11/2008
Re: tolong saya selesaikan soalan ni..
ok..terima kasih dh dapat dh...
harith_azka- MBF New Member

- Number of posts: 4
Registration date: 08/12/2010
Re: tolong saya selesaikan soalan ni..
banyakkan latihan agar lebih faham & mahir...
_________________mbf...


Cikgu X- Special Rank
- Number of posts: 3180
Registration date: 12/11/2008
Re: tolong saya selesaikan soalan ni..
atau satu lagi cara cuba begini ja:
since pembawah /denominator boleh disamakan jadi boleh asingkan no bulat dn pecahan.mudahkan dn selesai jln pndek.
5 1/6 - 3 2/3=
(5-3) + (1/6 - 2/3)=
2+ (1/6 - (2x2)/(3x2))=
2+ (1/6 - 4/6)
= 2-3/6
= 2- 1/2
= 1 1/2
=====
since pembawah /denominator boleh disamakan jadi boleh asingkan no bulat dn pecahan.mudahkan dn selesai jln pndek.
5 1/6 - 3 2/3=
(5-3) + (1/6 - 2/3)=
2+ (1/6 - (2x2)/(3x2))=
2+ (1/6 - 4/6)
= 2-3/6
= 2- 1/2
= 1 1/2
=====
isadora- MBF Junior Member

- Number of posts: 30
Humor: witty
Registration date: 17/09/2010

Re: tolong saya selesaikan soalan ni..
saya tak paham tolong jelaskan:scratch:
logesking- MBF New Member

- Number of posts: 1
Age: 15
Location: seremban
Registration date: 22/12/2010
Re: tolong saya selesaikan soalan ni..
322 ten thousands what means ? ?
iyad- MBF New Member

- Number of posts: 6
Registration date: 14/12/2010
Re: tolong saya selesaikan soalan ni..
iyad wrote:322 ten thousands what means ? ?![]()
answer : 3 220 000
meaning u just have to add 0's afta the number given.how many 0's?read the question if ten=0, if hundred=00 and so on..
for example: 432 hundred = 43200, 432 thousands = 432000
hope u understand.. =)
hech 81- MBF New Member

- Number of posts: 15
Registration date: 15/12/2010
Re: tolong saya selesaikan soalan ni..
thank you.....for this information
iyad- MBF New Member

- Number of posts: 6
Registration date: 14/12/2010
Re: tolong saya selesaikan soalan ni..
u r welcome..dont forget to do a lots of practice to familiarize with the question.. =)
hech 81- MBF New Member

- Number of posts: 15
Registration date: 15/12/2010
Re: tolong saya selesaikan soalan ni..
ok..... i promise...
iyad- MBF New Member

- Number of posts: 6
Registration date: 14/12/2010
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